1. Regular Guest
Join Date
Jan 2003
Posts
252
Post Likes

## dehumidification of OA

How many lbs/hr of dehumidification (latent heat) is required to condition 2000 cfm of 93Fdb/75wb air down to 75db/61wb

does 51 lbs/hr sound right?

2. How did you calculate to get 51?

3. Regular Guest
Join Date
Apr 2011
Posts
23
Post Likes
Don't you need to know the relative humidity to do this?

4. Regular Guest
Join Date
Apr 2011
Posts
10
Post Likes

5. Professional Member*
Join Date
Jun 2006
Location
Charlotte, NC area
Posts
108
Post Likes
I used a psych calculator and came up with 53.3 lb/hr

Here are the engineering geek details if you are interested:
Assuming sea level, air at 93/75 has a density of 14.26 Cu Ft ./lb and contains 102.27 Grains/lb of moisture. At 75/61 it contains 57.91 GR/Lb.

2000CF/min /14.26 cf/lb = 140.25 lb/min X 60 min/hr = 8415 lb/hr of dry air.

The moisture removed = 102.27 gr/lb – 57.91 gr/lb = 44.36 gr/lb.

So 8415 lb/hr X 44.36 gr/lb = 373,295 gr/hr divide by 7000 gr/lb = 53 lb/hr

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•

## Related Forums

The place where Electrical professionals meet.