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  1. #1
    Join Date
    Jan 2003
    Posts
    252

    dehumidification of OA

    How many lbs/hr of dehumidification (latent heat) is required to condition 2000 cfm of 93Fdb/75wb air down to 75db/61wb


    does 51 lbs/hr sound right?

  2. #2
    Join Date
    Feb 2006
    Location
    SouthEastern Virginia
    Posts
    1,076
    How did you calculate to get 51?
    It might get loud!

  3. #3
    Join Date
    Apr 2011
    Posts
    23
    Don't you need to know the relative humidity to do this?

  4. #4
    Join Date
    Apr 2011
    Posts
    10
    I believe your looking at about 8 tons

  5. #5
    Join Date
    Jun 2006
    Location
    Charlotte, NC area
    Posts
    87
    I used a psych calculator and came up with 53.3 lb/hr

    Here are the engineering geek details if you are interested:
    Assuming sea level, air at 93/75 has a density of 14.26 Cu Ft ./lb and contains 102.27 Grains/lb of moisture. At 75/61 it contains 57.91 GR/Lb.

    2000CF/min /14.26 cf/lb = 140.25 lb/min X 60 min/hr = 8415 lb/hr of dry air.

    The moisture removed = 102.27 gr/lb – 57.91 gr/lb = 44.36 gr/lb.

    So 8415 lb/hr X 44.36 gr/lb = 373,295 gr/hr divide by 7000 gr/lb = 53 lb/hr

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