Anyone figure out how to turn an old fan blower into a windmill to make power?
Or work on any wind systems?
back of the envelope calc.
13 sq. ft blade swept area
air weighs 1# for each 13 cu. ft.
40x13 = 520 cu. ft. per second = 40# of air per second through the fan =1.3 hp but you can only get half of this, maximum, out of the wind.
Make a prototype.
A battery powered drill run in reverse is a DC generator.
You hang a smaller version of this large fan out of the window of a car moving at 40'/sec.
Don't get on the evening news.
Sooooo....... what does that mean for me?
Just curious because I tore an old leibart out and those fans spun! I left in the customers scrap iron pile for a month and I mean those fans spun! Fast, and with little wind.
You need to hook it up to a generator (a junkyard auto DC generator?) with a load and a wattmeter. Try a prototype. The most difficult part may be finding a gear train/belt drive that gives you max. power into the gen.
Originally Posted by deux
Or hook it to a home-made Prony Brake
You'll need a tach in any case.
I took an ECM - put a large squirl cage blower wheel on it - put a belly band mounting on the motor - placed it 3 ft away from an old belt driven blower and produced 60Vac 3ph (with the end bell off the motor)
It may have been more efficient with a BLADED fan, but I am interested in VAWT tecnology so I don't have to commutate with the wind dirrection.
I have been told those ECMs are 3/4 HP so you do the math.
Check into VAWT (Vertical Axis Wind Turbine) on Youtube.
Or check this site out
Those who dance, appear insane to those who do not hear the music.
Those who believe, appear ignorant to those who do not know God.
You need to load down the 60v with a variable resistor. When it drops to 30v you have found the maximum power point.
Originally Posted by cehs
30v into a 120v 1200w 12 ohm non-electronic toaster is (30^2)/12 = 75w.
Alternatively, if you short the 60v gen. and you get 1A, the max power you can get from this gen. is 900/60 = 15w.
The average house presents a 1 kw avg. load; (240^2)/1000 = a 60 ohm load at 240v. Peak load may be 40 kw but you could handle this with a battery bank and invertor.
Are we doin' DIY?