# Thread: True or False?

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OK so it was the 2nd last thing I had to say about the subject... Great Argument Mark, but you still can't convince me that the air that has contacted the coil surface isn't cooling the rest of the air it collides with below the dew point. At least the "bypass" air.

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depends on the bypass factor.

a iced up coil with 100&#37; bypass factor doesn't cool anything.

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That's true... and that's why ya can't beat a cold beer (or 5). Have a good night guys.

4. Ok, another question for teh dr.

In order for the air that contacted the coil to cool the air that didn't contact the coil to below dewpoint temp. How many BTUs would have to be exchanged.

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Originally Posted by beenthere
Ok, another question for teh dr.

In order for the air that contacted the coil to cool the air that didn't contact the coil to below dewpoint temp. How many BTUs would have to be exchanged.

Some.

6. Originally Posted by air-doctor
Some.
LOL..

Is that some. Or is that sum.

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I can almost see the lil wheels in your head spinning... good to get all you guys thinking. Some good arguments were posted to this question and actually it got way more attention than I anticipated.

8. sum = 900 BTUH per pound

9. Measure and prove yourself wrong, doc.

Use the psych chart.

The air leaving the evaporator is not 100&#37; RH.

If your measuring device indicates that, you need a more sensitive device.

As noted earlier, the bypass are doesn't bypass the entire coil. It goes between the fins without making contact. Thus, it is not cooled below or to its dew point.

10. Originally Posted by Ed Janowiak
sum = 900 BTUH per pound
This time, I was trying to make him thing.

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You geniuses better inform NATE then... cuz its a question on some of their tests and the answer is true according to them.

12. NATE isn't always right.

13. Originally Posted by jrbenny
NATE isn't always right.

Surely you jest.

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