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Thread: Superheat

  1. #1
    Join Date
    Dec 2004
    Posts
    440
    Target Superheat=(return wb x 3 - condensor intake drybulb -80) /2

    So let's say return wetbulb at evap. intake is 80
    and it is 80 degrees at the condensor intake


    80 x 3 = 240 - 80 - 80 = 80 divided by two = 40

    Under these circumstances you should
    have 40 degrees superheat?

  2. #2
    Join Date
    Apr 2002
    Location
    Dallas, TX
    Posts
    2,987
    Yes, but keep in mind that the equation you have is a simple linear correlation of some charging chart data. You don't know how accurate the correlation is at the conditions you state. And 40F superheat will be about the TD of the evaporator so charging to this superheat may prove difficult.

  3. #3
    Join Date
    Jan 2004
    Location
    Lancaster PA
    Posts
    68,307
    That would be right, + or - 5

    Although at that ID WB, and OD DB, I wouldn't expect the ID delta to be much more then 10 untill the WB dropped to the mid to low 70's.
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  4. #4
    Join Date
    May 2000
    Location
    Indianapolis, IN, USA
    Posts
    34,295
    In a rainforest that sounds close!

    Try a more normal scenario. How about 65wb and 85 out?

  5. #5
    Join Date
    Dec 2004
    Posts
    440
    Originally posted by BaldLoonie
    In a rainforest that sounds close!
    In Florida we often have high humidity. But
    how can you tell what the humidity is since
    I never gave the indoor dry bulb tempt.?

  6. #6
    Join Date
    Dec 2004
    Posts
    440
    Originally posted by BaldLoonie
    In a rainforest that sounds close!

    Try a more normal scenario. How about 65wb and 85 out?
    I never said you could not find some conditions
    where this equation works. I just wanted to
    know if it was always accurate. It is quite
    possible to have 80 degree indoor wet bulb
    and 85 degree or 90 degree indoor dry bulb.

  7. #7
    Join Date
    Dec 2004
    Posts
    440
    Where am I wrong?

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