If 11532 btu's were removed from 62 lbs of water at a 72 degrees f water temp , what would be the new temp of the water ?
Homework Question....appreciate some help with a formula.
Thanks
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If 11532 btu's were removed from 62 lbs of water at a 72 degrees f water temp , what would be the new temp of the water ?
Homework Question....appreciate some help with a formula.
Thanks
It takes 1 BTU to raise 1 pound of water 1 degree F.
understand the definition, still confused on how to answer the question.
Thanks for the response
Either there is a typo here or you're getting into phase change, too.
You're removing eleven thousand, five hundred and thirty two BTUs from sixty two pounds of water at seventy two degrees?
I typed the full words out to prevent confusion.
I ran a little math and this doesn't add up to a typical problem.
Are you adding or removing heat?
Also, moving thread to tech to tech. AOP is for equipment questions.
yes sir...removing 11532 btu from 62 lbs of 72 degree f water there is a change of state latent and sensible i think
here is another one 13080 btu were removed from 10 lbs of water at 218 degree f what would be the temp of the water
Thanks for the help
Formula: BTU's = Lbs x Deg x SH (specific heat of material)
Note: specific heat of water is 1.0.
So with a little Algerbra: Btu ÷ (Lbs x SH) = Deg.
Now to calculate Btu's required to lower temp from 72ºf to 32ºf (ICE), or 40ºf.
62 lbs x 40 deg x 1 SH = 2480 btu's
11532 - 2408 = 11408 btu's left at 32ºf
Change of State - Latent heat of Fusion
144 btu/lb to change liquid to ice : 62 lbs x 144 btu's = 8928 btus
Now we have used : 2480 (lowering temp to 32ºf) + 8928 (change of state) = 11408 btus
11532 - 11408 = 124 btus left
Note: specific heat of ice is 0.5
124 Btu's ÷ (62 Lbs x 0.5 SH) = 4 degs
32ºf (ice) - 4ºf = 28ºf (final temperature)
I converted to per pound because it was easier for me to follow, would have converted back at the end had I known its only 144 to ice. Guess I assumed more because there is so much energy in condensation.
BTW, What is that exact number?
Did not realize its 1 btu to drop ice 2 f, so would said 30 and gotten the answer wrong even knowing cost of getting to ice. Thanks for the formula and explanation on specific heat!
change of state at 212 degrees f 970 btu at this point
I remember in physics we had a question:
A round tub with 2' height, made of standard steel has a volume of 50 gallons at 50*, and it is filled with 15 gallons of 50*F water. How many gallons of boiling water would it take to over flow the tub, and at what temp would the water be? Answer to the nearest 0.001gal and 0.1*F.
I'm sure it's not as simple as 35.001 gallons and 98.6, and am dying to see the formula...